Walking Velocity and Displacement Calculation

How long does it take to walk at an average velocity of 1.2 m/s from the bus stop to the museum entrance?

Given data:

The time taken by object is 11.3 minutes.

The velocity given is 1.2 m/s.

It takes 11.3 minutes to walk at an average velocity of 1.2 m/s from the bus stop to the museum entrance.

Solution:

The displacement in this case can be calculated using the formula: displacement = velocity × time.

Given the velocity of 1.2 m/s and the time of 11.3 minutes (which is equivalent to 678 seconds),

displacement = 1.2 m/s × 678 s = 813.6 meters.

Therefore, the displacement from the bus stop to the museum entrance is 813.6 meters.

When calculating displacement in physics, it is important to consider both velocity and time. In this scenario, the time taken to walk from the bus stop to the museum entrance was given as 11.3 minutes, and the velocity was given as 1.2 m/s. By multiplying the velocity by the time, we can determine the displacement covered during the walk.

First, it is necessary to convert the time from minutes to seconds in order to have consistent units for time. Given that 1 minute is equal to 60 seconds, 11.3 minutes is equivalent to 678 seconds. Then, by multiplying the velocity of 1.2 m/s by the time of 678 seconds, we find that the displacement is 813.6 meters.

Understanding displacement is essential in physics as it measures the overall change in position of an object. In this case, the displacement value of 813.6 meters indicates the total distance covered from the starting point at the bus stop to the final destination at the museum entrance.

← Riding a bike in a pipe physics stunt challenge Finding volume of tennis balls and cylinder →