Stoichiometry Challenge: Calculate the Mass of Coke Needed to Produce CS2

Explanation:

Step 1: The balanced equation for the reaction is given below:

3C(s) + 2SO2(g) → CS2(s) + 2CO2(g)

Step 2: Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation. This is illustrated below:

Molar Mass of C = 12g/mol
Mass of C from the balanced equation = 3 x 12 = 36g
Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol. From the balanced equation above, 36g of C reacted to produce 76g of CS2.

Step 3: Determination of the mass of C required to produce 950g of CS2. This is illustrated below:

From the balanced equation above, 36g of C reacted to produce 76g of CS2.

Therefore, Xg of C will react to produce 950g of CS2 i.e Xg of C = (36 x 950)/76

Xg of C = 450g

From the calculations made above, 450g of coke (C) is needed to produce 950g of CS2.

Final answer: To produce 950 grams of CS2, approximately 450 grams of coke is needed.

Explanation: In order to determine the mass of coke needed to produce 950 grams of CS2, we need to use stoichiometry to relate the mass of CS2 to the mass of coke. Since the actual yield of CS2 is 86.0% of the theoretical yield, we can calculate the theoretical yield first.

Let's assume the theoretical yield of CS2 is x grams. Since the actual yield is 86.0% of the theoretical yield, the actual yield is 0.86x grams.

Now we can set up a proportion to solve for x:
x g coke / 1 = 0.86x g CS2 / 950 g CS2

Solving for x, we find x = 450g coke. Therefore, approximately 450 grams of coke is needed to produce 950 grams of CS2.