Reviewing Stoichiometry Equation: 2KClO3 → 2KCl + 3O2

Understanding Stoichiometry:

Stoichiometry of the reaction: 2 KClO₃ → 2 KCl + 3 O₂ The stoichiometry of a chemical reaction is the calculation of quantitative relationships between reactants and products in a balanced chemical equation. In this case, the equation represents the decomposition of potassium chlorate (KClO₃) into potassium chloride (KCl) and oxygen gas (O₂). To determine the number of moles of oxygen produced when 2 moles of potassium chlorate (KClO₃) decompose, we utilize the stoichiometry of the reaction: Calculations: 2 moles KClO₃ → 3 moles O₂ 2 moles of KClO₃ decompose, so the question is: How many moles of O₂ are produced? Using the stoichiometry, we can calculate the answer: 2 moles of KClO₃ x (3/2) = 3 moles of O₂ Therefore, when 2 moles of potassium chlorate decompose, 3 moles of oxygen gas are produced. Hope this explanation helps clarify the concept of stoichiometry in this reaction!

How many moles of oxygen are produced when 2 mol of potassium chlorate (KClO3) decompose?

The answer is 3. Explanation: 2 mol of potassium chlorate x (3/2) = 3.

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