Making Dilutions: Calculating the Number of Grams of NaHCO3

How can we determine the number of grams of NaHCO3 in a 2.1 M solution?

Given the molarity of 2.1 M, what is the process to calculate the number of grams of NaHCO3 present in one liter of the solution?

Answer:

To determine the number of grams of NaHCO3 in a 2.1 M solution, we can follow a simple calculation involving the molarity and the molar mass of NaHCO3.

When dealing with a 2.1 M solution of NaHCO3, we first need to understand the concept of molarity (M). Molarity is defined as the number of moles of solute per liter of solution. In this case, a 2.1 M solution means there are 2.1 moles of NaHCO3 per liter of solution.

The next step is to calculate the number of grams of NaHCO3 present in one liter of the solution. This can be done by multiplying the molarity by the molar mass of NaHCO3. The molar mass of NaHCO3 is 84.01 grams per mole.

Therefore, in a 2.1 M NaHCO3 solution, there would be 2.1 moles/L x 84.01 g/mol = 176.221 grams of NaHCO3 per liter of solution.