Gas Law Problem Solving: Stay Positive and Solve It with Ease!

1. What is the volume of a gas at -150°C if it had a volume of 693 mL at 45°C?

Options:
A. 268.047 mL
B. 318.268 mL
C. 423.123 mL
D. 589.543 mL

Answer:

The volume of the gas at -150°C would be 268.047 mL.

In this gas law problem, we are given the initial volume of the gas (V1 = 693 mL) at a certain temperature (T1 = 45°C) and asked to find the volume of the gas at a different temperature (T2 = -150°C). We can use the formula V1/T1 = V2/T2 to solve for V2 in this scenario.

First, we need to convert the temperatures to Kelvin by adding 273 to the Celsius temperatures. So, T1 = 45°C + 273 = 318 K and T2 = -150°C + 273 = 123 K.

Now, we can plug in the values we know into the formula:
693 mL / 318 K = V2 / 123 K

Cross multiply to solve for V2:
318 * V2 = 693 * 123
V2 = (693 * 123) / 318
V2 = 85239 / 318
V2 = 268.047 mL

Therefore, the volume of the gas at -150°C would be 268.047 mL. By staying positive and applying the gas law formula correctly, we can easily solve complex problems like this one!

← Chemistry challenge calculating grams of phosphoric acid How to find the measure of angle dbc →