Exploring the Volume of a Ca(OH)2 Solution

How was the 0.530 M Ca(OH)2 solution prepared?

The 0.530 M Ca(OH)2 solution was prepared by dissolving 36.0 grams of Ca(OH)2 in enough water. What is the total volume of the solution thus formed?

Group of answer choices:
1. 0.720 liters
2. 0.917 liters
3. 1.03 liters
4. 1.21 liters

Total Volume of the Solution

The total volume of the solution is 0.917 liters.

To find the total volume of the 0.530 M Ca(OH)2 solution, we need to use the formula: Molarity (M) = moles of solute/volume of solution (in liters).

Given that the molarity of the solution is 0.530 M, we need to find the volume of the solution. First, we need to convert the mass of Ca(OH)2 into moles.

The molar mass of Ca(OH)2 is 74.09 g/mol.
36.0 grams of Ca(OH)2 × (1 mol / 74.09 g) = 0.486 mol

Now, we can use the formula to find the volume of the solution:
0.530 M = 0.486 mol/volume of solution (in liters)

Rearranging the formula, we have:
Volume of solution (in liters) = 0.486 mol / 0.530 M
Volume of solution = 0.917 liters

Therefore, the total volume of the solution is 0.917 liters. The correct answer choice is 0.917 liters.