Chemistry Problem Solving: Calculating Oxygen Atoms in Carbon Tetrachloride and Column Height of Copy Paper Sheets

How many oxygen atoms are present in 61.00 g of carbon tetrachloride?

Based on the given data, what is the correct calculation to determine the number of oxygen atoms in carbon tetrachloride?

a. 2.39 x 10²³

b. 1.19 x 10²⁴

Answer:

The correct answer is: a. 2.39 x 10²³

To find the number of oxygen atoms in 61.00 g of carbon tetrachloride, we need to use the concept of molar mass and Avogadro's number. Start by calculating the molar mass of carbon tetrachloride (CCl4). The molar mass is the sum of the atomic masses of all the atoms in the compound.

The atomic mass of carbon (C) is 12.01 g/mol.

The atomic mass of chlorine (Cl) is 35.45 g/mol.

Carbon tetrachloride contains 1 carbon atom and 4 chlorine atoms.

So, the molar mass of carbon tetrachloride is (1 x 12.01) + (4 x 35.45) = 153.82 g/mol.

Now, we can use the molar mass to convert grams of carbon tetrachloride to moles.

Divide the given mass (61.00 g) by the molar mass (153.82 g/mol).

61.00 g / 153.82 g/mol = 0.396 moles of carbon tetrachloride.

Next, we use Avogadro's number to convert moles of carbon tetrachloride to the number of molecules.

Avogadro's number is approximately 6.022 x 10²³ molecules per mole.

Multiply the moles of carbon tetrachloride by Avogadro's number.

0.396 moles x (6.022 x 10^23 molecules/mol) = 2.39 x 10²³ molecules of carbon tetrachloride.

Therefore, there are approximately 2.39 x 10²³ oxygen atoms present in 61.00 g of carbon tetrachloride.